Four resistances of 15 Ω , 12 Ω , 4 Ω  and  10 Ω respectively in cyclic order to form Whetstone's network. The resistance that is to be connected in parallel with the resistance of 10 Ω  to balance the network is

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  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    a month ago

    10 R 10 + R × 12 = 15 × 4 on solving

    R = 10 Ω

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Let V? = 10V, V? = xV, V? = 0V, and V? = yV.
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