A Block of ice of mass 120g at temperature 0 ° C  is put in 300g of water at 2 5 ° C .  The xg of ice melts as the temperature of the water reaches 0 ° C .  The value of x is _________.

[Use specific heat capacity of water = 4200Jkg-1K-1, Latent heat of ice = 3.5 * 105Jkg-1]

3 Views|Posted 7 months ago
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1 Answer
P
7 months ago

Using concept of calorimeter, we can write

Gain in heat = Loss in heat

x*L=mcΔTx*3.5*105=3001000*25*4200

x=300*25*42001000*3.5*105=3*25*4235*1000=901000kg=90gm

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Physics Thermodynamics 2025

Physics Thermodynamics 2025

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