A block of mass 40kg slides over a surface, when a mass of 4kg is suspended through an inextensible massless string passing over frictionless pulley as shown below.

The coefficient of kinetic friction between the surface and block is 0.02. The acceleration of block is. (given g = 10 ms^-2.)

Option 1 - 1 ms-2

Option 2 - 1/5 ms-2

Option 3 - 4/5 ms-2

Option 4 - 8/11 ms-2

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Vishal Baghel | Contributor-Level 10

4 months ago

Correct Option - 4

Detailed Solution:

According to Newton's laws of motion, we can write

4a = 4g – T . (1), and

40a = T - f_k = T - $μ$ (40g) ……………… (2)

Adding equations (1) and (2), we can write

44a = 40 – 0.02 * (400) = 32

$\Rightarrow a = \frac{32}{44} = \frac{8}{11} m / s^{2}$

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A block of mass 40kg slides over a surface, when a mass of 4kg is suspended through an inextensible massless string passing over frictionless pulley as shown below. The coefficient of kinetic friction between the surface and block is 0.02. The acceleration of block is. (given g = 10 ms-2.)

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