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A block of mass m  attached to a massless spring is performing oscillatory motion of amplitude ' A ' on a frictionless horizontal plane. If half of the mass of the block breaks off when it is passing through its equilibrium point, the amplitude of oscillation for the remaining system become f A . The value of f  is:

Option 1 -

1 2

Option 2 -

1 2

Option 3 -

2

Option 4 -

1

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 2


    Detailed Solution:

    V m a x = A ' ω ' = A ω

    A ' k m / 2 = A k m A ' = A 2

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