A block rests on an inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between block and the plane is 0.8. If the frictional force on the block is 10 N, then mass of block (in kg) (Take g = 10 m/s2 )
A block rests on an inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between block and the plane is 0.8. If the frictional force on the block is 10 N, then mass of block (in kg) (Take g = 10 m/s2 )
Option 1 - <p>2.0</p>
Option 2 - <p>2.5</p>
Option 3 - <p>4.0</p>
Option 4 - <p>1.5</p>
5 Views|Posted 3 months ago
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1 Answer
A
Answered by
3 months ago
Correct Option - 1
Detailed Solution:
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= 0.92 * 1260 = 1161 m/s
For 2 kg block
T – 2g sin37 = 2a . (i)
For 4 kg block
4g – 2T =
2g – T = a . (ii)
T = (2g – a)
2g – a – 2g × = 2a
3a = 2g ×
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