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Find the acceleration of 2 kg block shown in the diagram. (neglect friction)

 

Option 1 -

4 g 1 5

Option 2 -

2 g 1 5

Option 3 -

g 1 5

Option 4 -

2 g 3

0 2 Views | Posted 4 weeks ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    4 weeks ago
    Correct Option - 1


    Detailed Solution:

    For 2 kg block

    T – 2g sin37 = 2a        . (i)

    For 4 kg block

    4g – 2T =  4 a 2

    2g – T = a                    . (ii)

    T = (2g – a)

    2g – a – 2g ×  3 5  = 2a

    3a = 2g ×  2 5

    a = 4 g 1 5

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