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Physics Laws of Motion Physics Class 11th Laws of Motion

Find the acceleration of 2 kg block shown in the diagram. (neglect friction)

Option 1 -

$\frac{4 g}{15}$

Option 2 -

$\frac{2 g}{15}$

Option 3 -

$\frac{g}{15}$

Option 4 -

$\frac{2 g}{3}$

2 Views | Posted a week ago

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1 Answer

Answered by

alok kumar singh | Contributor-Level 10

a week ago

Correct Option - 1

Detailed Solution:

For 2 kg block

T – 2g sin37 = 2a . (i)

For 4 kg block

4g – 2T = $\frac{4 a}{2}$

2g – T = a . (ii)

T = (2g – a)

2g – a – 2g × $\frac{3}{5}$ = 2a

3a = 2g × $\frac{2}{5}$

$a = \frac{4 g}{15}$

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