A body of mass 10kg is acted upon by two perpendicular forces, 6N and 8N. The resultant acceleration of the body is

(a) 1 m s-2 at an angle of tan-1(3/4) w.r.t. 6N force.

(b) 0.2 m s-2 at an angle of tan-1(3/4) w.r.t. 6N force.

(c) 1 m s-2 at an angle of tan-1(3/4) w.r.t.8N force.

(d) 0.2 m s-2 at an angle of tan-1(3/4) w.r.t.8N force.

2 Views|Posted 6 months ago
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6 months ago

This is a Multiple Choice Questions type Questions as classified in NCERT Exemplar

Answer- a, c

Explanation – mass m= 10kg

F1 =6N, F2= 8N

Resultant force F= 36 + 64 = 10 N

a=f/m= 10/10= 1m/s2

let θ 1 be the angle between R and F1

tan θ 1=8/6=4/3

θ 1= tan θ 1 (4/3) w.r.t F1=6N

let θ 2 be the angle between F and F2

tan θ 1=8/6

...Read more

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Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025

Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025

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