A body of mass 10kg is acted upon by two perpendicular forces, 6N and 8N. The resultant acceleration of the body is
(a) 1 m s-2 at an angle of tan-1(3/4) w.r.t. 6N force.
(b) 0.2 m s-2 at an angle of tan-1(3/4) w.r.t. 6N force.
(c) 1 m s-2 at an angle of tan-1(3/4) w.r.t.8N force.
(d) 0.2 m s-2 at an angle of tan-1(3/4) w.r.t.8N force.
A body of mass 10kg is acted upon by two perpendicular forces, 6N and 8N. The resultant acceleration of the body is
(a) 1 m s-2 at an angle of tan-1(3/4) w.r.t. 6N force.
(b) 0.2 m s-2 at an angle of tan-1(3/4) w.r.t. 6N force.
(c) 1 m s-2 at an angle of tan-1(3/4) w.r.t.8N force.
(d) 0.2 m s-2 at an angle of tan-1(3/4) w.r.t.8N force.
This is a Multiple Choice Questions type Questions as classified in NCERT Exemplar
Answer- a, c
Explanation – mass m= 10kg
F1 =6N, F2= 8N

Resultant force F=
a=f/m= 10/10= 1m/s2
let 1 be the angle between R and F1
tan 1=8/6=4/3
1= tan 1 (4/3) w.r.t F1=6N
let 2 be the angle between F and F2
tan 1=8/6
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Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025
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