A body of mass M at rest explodes into pieces, in the ratio of masses 1 : 1: 2. Two smaller pieces fly off perpendicular to each other with velocities of 30 ms-1 and 40 ms-1 respectively. The velocity of the third piece will be:
A body of mass M at rest explodes into pieces, in the ratio of masses 1 : 1: 2. Two smaller pieces fly off perpendicular to each other with velocities of 30 ms-1 and 40 ms-1 respectively. The velocity of the third piece will be:
Option 1 -
15 ms-1
Option 2 -
25 ms-1
Option 3 -
35 ms-1
Option 4 -
50 ms-1
-
1 Answer
-
Correct Option - 2
Detailed Solution:Let ‘v’ be the velocity of third piece
com along x-axis
M × 0 = M1vx + M3v’x
Com along y-a
...more
Similar Questions for you
Let ‘x’ be the value of one division on main scale
Let ‘y’ be the value of one division on vernier
Now given
50y = 49 x
Let ‘h’ be the height at which velocity becomes equal to magnitude of Acceleration

v = g = 10
v = u + at
10 = 0 + 10t
t = 1 sec
= 5m
By conservation of Angular momentum
Li = Lf

Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers