In the arrangement shown in figure a1, a2, a3 and a4 are the accelerations of masses m1, m2, m3 and m4 respectively. Which of the following relation is true for this arrangement?

∑T→.a→=0 T2a1+T4a2+T8a3+T8a4=0 ⇒4a1+2a2+a3+a4=0

In the arrangement shown in figure a₁, a₂, a₃ and a₄ are the accelerations of masses m₁, m₂, m₃ and m₄ respectively. Which of the following relation is true for this arrangement?

Option 1 - 4a1 + 2a2 + a3 + a4 = 0

Option 2 - a1 + 4a2 + 3a3 + a4 = 0

Option 3 - a1 + 4a2 + 3a3 + 2a4 = 0

Option 4 - 2a1 + 2a2 + 3a3 + a4 = 0

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Vishal Baghel | Contributor-Level 10

6 months ago

Correct Option - 1

Detailed Solution:

$\sum_{}^{} \vec{T} . \vec{a} = 0$

$\frac{T}{2} a_{1} + \frac{T}{4} a_{2} + \frac{T}{8} a_{3} + \frac{T}{8} a_{4} = 0$

$\Rightarrow 4 a_{1} + 2 a_{2} + a_{3} + a_{4} = 0$

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