A capacitor C is fully charged with voltage V?. After disconnecting the voltage source, it is connected in parallel with another uncharged capacitor of capacitance C/2. The energy loss in the process after the charge is distributed between the two capacitor is:

Option 1 -

1/3 CV₀²

Option 2 -

1/4 CV₀²

Option 3 -

1/6 CV₀²

Option 4 -

1/2 CV₀²

2 Views | Posted a month ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

a month ago

Correct Option - 1

Detailed Solution:

Q? = CV?
U? = ½CV? ²
q? = (q? C)/ (C + C/2) = 2q? /3

q? = (q? (C/2)/ (C + C/2) = q? /3; Uf = q? ²/2C + q? ²/2 (C/2)
= (4q? ²/9x2C) + (q? ²/9C)
= (6q? ²/18C) = q? ²/3C = CV? ²/3

Energy loss in the process = U? – Uf
= ½CV? ² - CV? ²/3
= CV? ²/6

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