A capacitor is discharging through a resistor R. Consider in time t1 the energy stored in the capacitor reduces to half of its initial value and in time t2, the charge stored in the capacitor reduces to half of its initial value and in time t2 the charge stored reduces to one eight of its initial value. The ratio t1/t2 will be

Option 1 -

1/2     

Option 2 -

1/3

Option 3 -

1/4 

Option 4 -

1/6

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    2 months ago
    Correct Option - 4


    Detailed Solution:

    According to Law of discharging of capacitor, we can write

    Q=Q0etτQ28=Q0et2τt23τln (2), and

    U=Q22C=Q022Ce2tτ12 (Q022C)=Q022Ce2tτt1=τ2ln (2)

    t1t2=16

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