A car of mass m starts from rest and acquires a velocity along east v = vȋ (v>0) in two seconds. Assuming the car moves with uniform acceleration, the force exerted on the car is
(a) mv/2 eastward and is exerted by the car engine.
(b) mv/2 eastward and is due to the friction on the tyres exerted by the road.
(c) more than mv/2 eastward exerted due to the engine and overcomes the friction of the road.
(d) mv/2 exerted by the engine .
A car of mass m starts from rest and acquires a velocity along east v = vȋ (v>0) in two seconds. Assuming the car moves with uniform acceleration, the force exerted on the car is
(a) mv/2 eastward and is exerted by the car engine.
(b) mv/2 eastward and is due to the friction on the tyres exerted by the road.
(c) more than mv/2 eastward exerted due to the engine and overcomes the friction of the road.
(d) mv/2 exerted by the engine .
This is a Multiple Choice Questions type Questions as classified in NCERT Exemplar
Answer- b
Explanation – mass of car m =0
Initial velocity =0,
velocity at east direction = v?
Time =2s
So v=u+at,
v? =0+a (2)
so a =v/2?
F=ma = so force = mv/2 towards east.
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Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025
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