A car of mass m starts from rest and acquires a velocity along east v = vȋ (v>0) in two seconds. Assuming the car moves with uniform acceleration, the force exerted on the car is

(a) mv/2 eastward and is exerted by the car engine.

(b) mv/2  eastward and is due to the friction on the tyres exerted by the road.

(c) more than mv/2 eastward exerted due to the engine and overcomes the friction of the road.

(d) mv/2 exerted by the engine .

3 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago

This is a Multiple Choice Questions type Questions as classified in NCERT Exemplar

Answer- b

Explanation – mass of car m =0

Initial velocity =0,

velocity at east direction = v?

Time =2s

So v=u+at,

v? =0+a (2)

so a =v/2?

F=ma = m v 2 ?  so force = mv/2 towards east.

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Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025

Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025

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