A cell E1 of emf 6V and internal resistance 2 Ω  is connected with another cell E2 of emf 4V and internal resistance   8 Ω (as shown in the figure). The potential difference across points X and Y is:

 

Option 1 - <p>10.0V</p>
Option 2 - <p>2.0V</p>
Option 3 - <p>5.6V</p>
Option 4 - <p>3.6V</p>
3 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
A
5 months ago
Correct Option - 1
Detailed Solution:

i = 6 4 2 + 8 = 0 . 2 A

V x + 4 + 0 . 2 * 8 = V Y

V Y V X = 5 . 6 V

 

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Maths NCERT Exemplar Solutions Class 11th Chapter Eleven 2025

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