A coil of 0.01 H inductance and 1 ω resistance is connected to 200 V, 50 Hz AC supply. Find the impedance of the circuit and time lag between maximum alternating voltage and current.
This is a short answer type question as classified in NCERT Exemplar
L= 0.01H
R= 1ohm
Voltage =200V
Frequency = 50Hz
Z= = = =3.3ohm
tan = = 3.14
= tan-13.14=72
=72
= /w= = s
<p><span data-teams="true">This is a short answer type question as classified in NCERT Exemplar</span></p><p>L= 0.01H</p><p>R= 1ohm</p><p>Voltage =200V</p><p>Frequency = 50Hz</p><p>Z= <math><mroot><mrow><mrow><msup><mrow><mrow><mi>R</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msup><mo>+</mo><msubsup><mrow><mrow><mi>X</mi></mrow></mrow><mrow><mrow><mi>L</mi></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msubsup></mrow></mrow><mrow></mrow></mroot></math> = <math><mroot><mrow><mrow><msup><mrow><mrow><mn>1</mn></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msup><mo>+</mo><mo> (</mo><msup><mrow><mrow><mn>2</mn><mo>×</mo><mn>3.14</mn><mo>×</mo><mn>50</mn><mo>×</mo><mn>0.01</mn><mo>)</mo></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></msup></mrow></mrow><mrow></mrow></mroot></math> = <math><mroot><mrow><mrow><mn>10.86</mn></mrow></mrow><mrow></mrow></mroot></math> =3.3ohm</p><p>tan <math><mi>∅</mi><mo>=</mo><mfrac><mrow><mrow><mi>w</mi><mi>L</mi></mrow></mrow><mrow><mrow><mi>R</mi></mrow></mrow></mfrac></math> = <math><mfrac><mrow><mrow><mn>2</mn><mi>π</mi><mi>f</mi><mi>L</mi></mrow></mrow><mrow><mrow><mi>R</mi></mrow></mrow></mfrac><mo>=</mo><mfrac><mrow><mrow><mn>2</mn><mo>×</mo><mn>3.14</mn><mo>×</mo><mn>50</mn><mo>×</mo><mn>0.01</mn></mrow></mrow><mrow><mrow><mn>1</mn></mrow></mrow></mfrac></math> = 3.14</p><p><math><mi>∅</mi></math> = tan-13.14=72</p><p><math><mi>∅</mi></math> =72 <math><mfrac><mrow><mrow><mi>π</mi></mrow></mrow><mrow><mrow><mn>180</mn></mrow></mrow></mfrac><mi>r</mi><mi>a</mi><mi>d</mi></math></p><p><math><mo>? </mo><mi>t</mi></math> = <math><mi>∅</mi></math> /w= <math><mfrac><mrow><mrow><mn>72</mn><mi>π</mi></mrow></mrow><mrow><mrow><mn>180</mn><mo>×</mo><mn>2</mn><mi>π</mi><mo>×</mo><mn>50</mn></mrow></mrow></mfrac></math> = <math><mfrac><mrow><mrow><mn>1</mn></mrow></mrow><mrow><mrow><mn>250</mn></mrow></mrow></mfrac></math> s</p>
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