A cricket ball of mass 150 g has an initial velocity u=(3ȋ+4ĵ )m/s and a final velocity v=-(3ȋ+4ĵ) after being hit. The change in momentum (final momentum-initial momentum) is (in kg m s^-1)

(a) Zero

(b)-(0.45ȋ+0.6ĵ)

(c) –(0.9j+1.2ĵ) 

(d) -5(ȋ+ĵ)ȋ

<p>This is a Multiple Choice&nbsp; type Questions as classified in NCERT Exemplar</p><p><strong>Answer- c</strong></p><p><strong>Explanation</strong>- given u= (3? +4? )m/s</p><p>And v= - (3? +4? )m/s, and mass of ball is 150g=0.15kg</p><p>Change in momentum = final momentum – initial momentum</p><p>&nbsp;= mv-mu</p><p>= m (v-u) = 0.15 [- (3? +4? )- (3? +4? )]</p><p>= - [0.15<span contenteditable="false"> <math> <mo>×</mo> <mn>6</mn> <mi>i</mi> <mo>+</mo> <mn>0.15</mn> <mo>×</mo> <mn>8</mn> <mi>j</mi> </math> </span>]</p><p>= - [0.9? +1.2? ]</p><p><span contenteditable="false"> <math> <mo>? </mo> </math> </span>P =- [0.9? +1.2? ]</p>

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