A cricket ball of mass 150 g has an initial velocity u=(3ȋ+4ĵ )m/s and a final velocity v=-(3ȋ+4ĵ) after being hit. The change in momentum (final momentum-initial momentum) is (in kg m s-1)
(a) Zero
(b)-(0.45ȋ+0.6ĵ)
(c) –(0.9j+1.2ĵ)
(d) -5(ȋ+ĵ)ȋ
A cricket ball of mass 150 g has an initial velocity u=(3ȋ+4ĵ )m/s and a final velocity v=-(3ȋ+4ĵ) after being hit. The change in momentum (final momentum-initial momentum) is (in kg m s-1)
(a) Zero
(b)-(0.45ȋ+0.6ĵ)
(c) –(0.9j+1.2ĵ)
(d) -5(ȋ+ĵ)ȋ
This is a Multiple Choice type Questions as classified in NCERT Exemplar
Answer- c
Explanation- given u= (3? +4? )m/s
And v= - (3? +4? )m/s, and mass of ball is 150g=0.15kg
Change in momentum = final momentum – initial momentum
= mv-mu
= m (v-u) = 0.15 [- (3? +4? )- (3? +4? )]
= - [0.15 ]
= - [0.9? +1.2?
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Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025
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