A cricket ball of mass 150 g has an initial velocity u=(3ȋ+4ĵ )m/s and a final velocity v=-(3ȋ+4ĵ) after being hit. The change in momentum (final momentum-initial momentum) is (in kg m s-1)

(a) Zero

(b)-(0.45ȋ+0.6ĵ)

(c) –(0.9j+1.2ĵ) 

(d) -5(ȋ+ĵ)ȋ

4 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago

This is a Multiple Choice  type Questions as classified in NCERT Exemplar

Answer- c

Explanation- given u= (3? +4? )m/s

And v= - (3? +4? )m/s, and mass of ball is 150g=0.15kg

Change in momentum = final momentum – initial momentum

 = mv-mu

= m (v-u) = 0.15 [- (3? +4? )- (3? +4? )]

= - [0.15 * 6 i + 0.15 * 8 j ]

= - [0.9? +1.2?

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Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025

Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025

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