A current of 10 A exists in a wire of cross-sectional area of 5mm² with a drift velocity of 2*10⁻³ ms⁻¹. The number of free electrons in each cubic meter of the wire is ……………
A current of 10 A exists in a wire of cross-sectional area of 5mm² with a drift velocity of 2*10⁻³ ms⁻¹. The number of free electrons in each cubic meter of the wire is ……………
Option 1 - <p>2 x 10²⁵<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>1 x 10²³<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>2 x 10⁸<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>625 x 10²⁵</p>
4 Views|Posted 5 months ago
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5 months ago
Correct Option - 4
Detailed Solution:
Given:
- i = 10
- e = 1.6 x 10? ¹? C
- A = 5 x 10?
- V = 2 x 10? ³
The formula for current is I = neAV.
Rearranging for n (number of free electrons per unit volume):
n = I / (eAV)
n = 10 / (1.6 * 10? ¹? * 5 * 10? * 2 * 10? ³)
n = 625 * 10²?
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