A current of 10 A exists in a wire of cross-sectional area of 5mm² with a drift velocity of 2×10⁻³ ms⁻¹. The number of free electrons in each cubic meter of the wire is ……………
The formula for current is I = neAV. Rearranging for n (number of free electrons per unit volume): n = I / (eAV) n = 10 / (1.6 × 10? ¹? × 5 × 10? × 2 × 10? ³) n = 625 × 10²?
<p>Given:</p><ul type="disc"><li>i = 10</li><li>e = 1.6 x 10? ¹? C</li><li>A = 5 x 10? </li><li>V = 2 x 10? ³</li></ul><p>The formula for current is I = neAV.<br>Rearranging for n (number of free electrons per unit volume):<br>n = I / (eAV)<br>n = 10 / (1.6 × 10? ¹? × 5 × 10? × 2 × 10? ³)<br>n = 625 × 10²? </p>
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