A diatomic gas ( γ = 1 . 4 )  does 400 J of work when it is expanded isobarically. The heat given to the gas in the process is……………..J.

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    Answered by

    Payal Gupta | Contributor-Level 10

    2 months ago

    w = P Δ v = n R Δ T = 4 0 0 J  - (1)

    Q = n C P Δ T = n R y y 1 Δ T                

    Q = 1 4 4 × 4 0 0                

    Q = 1400 J

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Vishal Baghel

Process-AB Isobaric,                                                           

Process-AC Isothermal, and

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W2 < W1 < W3

 

V
Vishal Baghel

from newtan’s law of cooling :

d T d t = k ( T T 0 )

Using average value :

7 5 6 5 5 = k [ ( 7 5 + 6 5 ) 2 2 2 5 ]

( 6 5 T ) 5 = k [ ( 6 5 + T ) 2 2 5 ]

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Efficiency η = 5 0 %

η = ( 1 T 2 T 1 ) × 1 0 0 = 5 0

1 T 2 T 1 = 5 0 1 0 0 1 T 2 T 1 = 1 2  -(i)

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4 0 T 1 = . 6 5 . 5 0 = . 1 5 T 1 = 4 0 0 0 1 5 = 2 6 6 . 7 k

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At Resonance

XL = XC

then lL = lC

Now phasor diagram

for L & C

So, Net current = zero

= (lL+lC)

Therefore current through R circuit at resonance will be zero

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Payal Gupta

 r=mvqB

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