A force F = (î + 2ĵ + 3k)N acts at a point (4î + 3ĵ – k)m. Then the magnitude of torque about the point (î + 2ĵ + k)m will be √xN m. The value of x is
A force F = (î + 2ĵ + 3k)N acts at a point (4î + 3ĵ – k)m. Then the magnitude of torque about the point (î + 2ĵ + k)m will be √xN m. The value of x is
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1 Answer
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F = (i + 2j + 3k)N
r = (4 - 1)i + (3 - 2)j + (-1 - 1)k)
τ = r x F
= (3i + j - 2k) x (i + 2j + 3k)
ijk
3 1 -2 ⇒ I (3 + 4) - j (11) + (6-1)k
1 3
7i - 11j + 5k
|τ| = √121 + 25 + 49
|τ| = √195 ; x = 195
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