A force F = (40î + 10?)N acts on a body of mass 5 kg. If the body starts from rest, its position vector r at time t = 10s, will be :
A force F = (40î + 10?)N acts on a body of mass 5 kg. If the body starts from rest, its position vector r at time t = 10s, will be :
Option 1 - <p>(100î + 100ĵ) m<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>(400î + 100ĵ) m</p>
Option 3 - <p>(400î + 400ĵ) m<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>(100î + 400ĵ) m</p>
4 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
A
Answered by
7 months ago
Correct Option - 2
Detailed Solution:
a = F/m = (8î + 2? )
r = ut + ½ at²
r = 0 + ½ (8î + 2? ) 10²
r = 400î + 100?
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T1 = m (g + a)
T2 = m (g - a)
Apparent weight = mg – ma
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