A force on an object of mass 100g is ( 1 0 i ^ + 5 j ^ ) N . The position of that object at t = 2s is ( a i ^ + b j ^ ) m after starting from rest. The value of a b will be………

F → = 1 0 i ^ + 5 j ^ a → = 1 0 m i ^ + 5 m j ^ = 1 0 0 . 1 k g i ^ + 5 0 . 1 j ^ a → = 1 0 0 i ^ + 5 0 j ^ a x = 1 0 0 , a y = 5 0 S x = u t + 1 2 a t 2 = 0 * 2 + 1 2 * 1 0 0 * 2 * 2 Sx = 200 m a b = 2 0 0 1 0 0 = 2

A force on an object of mass 100g is $(10 \hat{i} + 5 \hat{j}) N .$ The position of that object at t = 2s is $(a \hat{i} + b \hat{j}) m$ after starting from rest. The value of $\frac{a}{b}$ $\frac{}{}$ will be………

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Raj Pandey | Contributor-Level 9

5 months ago

$\vec{F} = 10 \hat{i} + 5 \hat{j}$

$\vec{a} = \frac{10}{m} \hat{i} + \frac{5}{m} \hat{j}$

$= \frac{10}{0.1 k g} \hat{i} + \frac{5}{0.1} \hat{j}$

$\vec{a} = 100 \hat{i} + 50 \hat{j}$

$a_{x} = 100, a_{y} = 50$

$S_{x} = u t + \frac{1}{2} a t^{2}$

$= 0 * 2 + \frac{1}{2} * 100 * 2 * 2$

Sx = 200 m

$\frac{a}{b} = \frac{200}{100} = 2$

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