A metallic ring of mass m and radius l (ring being horizontal) is falling under gravity in a region having a magnetic- field. If z is the vertical direction, the z-component of magnetic field is Bz=B0(1+ z). If R is the resistance of the ring and if the ring falls with a velocity v, find the energy lost in the resistance. If the ring has reached a constant velocity, use the conservation of energy to determine v in terms of m, B,  and acceleration due to gravity g.

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8 months ago

This is a long answer type question as classified in NCERT Exemplar

? = B z π l 2 = B 0 ( 1 + λ z ) ( π l 2 )

According to faraday's law e= - d d t and also ohm's law V=IR

So by equating these two

We get Bo( π l 2 ) λ d z d t = I R

I= π l 2 B o λ v R

And energy lost/second = I2R= ( π l 2 λ ) 2 B o 2 v 2 R

As change in PE=mg d z d t = m g v but if we compare both energy then

Mgv= ( π l 2 λ ) 2 B o 2 v 2 R  or v=

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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