A multirange current meter can be constructed by using a galvanometer circuit as shown in figure. We want a current meter that can measure 10 mA, 100 mA and 1 mA using a galvanometer of resistance 10 Ω and that produces maximum deflection for current of 1 mA. Find S1 ,S2 and S3 that have to be used.
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- iG (G) = (I1-IG) (S1+S2+S3) for I1= 10mA
iG (G+S1) = (I2-IG) (S2+S3) for I2= 100mA
iG (G+S1+S2) = (I3-IG) (S3) for I3= 1A
S1= 1W, S2= 0,1W and S3= 0.01W
<p>This is a Long Answer Type Questions as classified in NCERT Exemplar</p><p><strong>Explanation- </strong>i<sub>G</sub> (G) = (I<sub>1</sub>-I<sub>G</sub>) (S<sub>1</sub>+S<sub>2</sub>+S<sub>3</sub>) for I<sub>1</sub>= 10mA</p><p>i<sub>G</sub> (G+S<sub>1</sub>) = (I<sub>2</sub>-I<sub>G</sub>) (S<sub>2</sub>+S<sub>3</sub>) for I<sub>2</sub>= 100mA</p><p>i<sub>G</sub> (G+S<sub>1</sub>+S<sub>2</sub>) = (I<sub>3</sub>-I<sub>G</sub>) (S<sub>3</sub>) for I<sub>3</sub>= 1A</p><p>S<sub>1</sub>= 1W, S<sub>2</sub>= 0,1W and S<sub>3</sub>= 0.01W</p>
There are two types of electricity - static and current. The current electricity is divided into Alternating Current (AC) and Direct Current (DC). Based on the production methods, electricity is divided into - heat, chemical, pressure, light and magnetism.
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