A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6MeV while that of fragments is 8.5MeV. The total gain in the Binding Energy in the process is:

Option 1 -

0.9MeV

Option 2 -

9.4MeV

Option 3 -

804MeV

Option 4 -

216MeV

0 2 Views | Posted 4 weeks ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    4 weeks ago
    Correct Option - 4


    Detailed Solution:

    The reaction is X²? → Y¹²? + Z¹²?
    Binding energies per nucleon are: X=7.6 MeV, Y=8.5 MeV, Z=8.5 MeV.
    Gain in binding energy (Q) = (Binding energy of products) - (Binding energy of reactants)
    Q = (120 × 8.5 + 120 × 8.5) - (240 × 7.6) MeV
    Q = (2 × 120 × 8.5) - (240 × 7.6) MeV = 2040 - 1824 = 216 MeV.

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