A nucleus with number 184 initially at rest emits an a-particle. If the Q value of the reaction is 5.5 MeV, calculate the kinetic energy of the α - particle.

Option 1 - 5.5 MeV

Option 2 - 5.38 MeV

Option 3 - 5.0 MeV

Option 4 - 0.12 MeV

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Answered by

Vishal Baghel | Contributor-Level 10

6 months ago

Correct Option - 2

Detailed Solution:

Using conservation of momentum

=> 180 V₁ = 4V₂

=> V₂ = 45 V₁

$Q = K E_{180} + K E_{α}$

$Q = \frac{1}{2} 180 V_{1}^{2} + \frac{1}{2} 4 V_{2}^{2}$

= $\frac{1}{2} * 180 * {(\frac{V_{2}}{45})}^{2} + \frac{1}{2} 4 V_{2}^{2}$

$K E_{α} = \frac{5.5 M e V}{(\frac{46}{45})} = 5.38 M e V$

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Physics Ncert Solutions Class 12th 2023

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