A parallel plate capacitor has plates of area A separated by distance ' ' between them. It is filled with a dielectric which has a dielectric constant that varies as where ' ' is he distance measured from one of the plates.
If , the total capacitance of the system is best given by the expression:
A parallel plate capacitor has plates of area A separated by distance ' ' between them. It is filled with a dielectric which has a dielectric constant that varies as where ' ' is he distance measured from one of the plates.
If , the total capacitance of the system is best given by the expression:
Capacitance of element
Capacitance of element,
Given:
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Please find the answer below
Now, using junction analysis
We can say, q? + q? + q? = 0
2 (x - 6) + 4 (x - 6) + 5 (x) = 0
x = 36/11, q? = 36 (5)/11 = 180/11
q? = 16.36µC
dC? = (ε? + kx)A / dx [For 0 < x < d/2]
1/C? = ∫ dx / (ε? + kx)A) from 0 to d/2
= (1/Ak) [ln (ε? + kx)] from 0 to d/2
= (1/kA) ln (1 + kd/ (2ε? )
C? = kA / ln (1 + kd/ (2ε? )
Similarly dC? = (ε? + k (d-x)A / dx [For d/2 ≤ x ≤ d]
C? = kA / ln (1 + kd/ (2ε? )
Clearly, C? = C? = C
For series combination:
C_eq = C? / (C?
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Physics Electrostatic Potential and Capacitance 2025
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