A particle A with a mass mA is moving with a velocity v and hits a particle B (mass mB) at rest (one dimensional motion). Find the change in the de-Broglie wavelength of the particle A. Treat the collision as elastic.

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    Answered by

    Pallavi Pathak | Contributor-Level 10

    3 months ago

    Explanation- according to law of conservation of momentum

    S0 mAv+mb0=mAv1+mBv2

    So mA(v-v1)= mBv2

    according to law of conservation of kinetic energy

    1/2mAv2=1/2mAv12+1/2mBv22

    So mA(v2-v12)= mBv22

    From above eqn we can say that v+v1=v2 or v=v2-v1

    So v1= mA-mBmA+mB v  and v22mAmA+mB v

    ? initial=h/mAv

    ? final=h/mAv1= h(mA+mB)ma(mA-mB)v

    d? = ? final- ? initial= hmAv{mA+mBmA-mB-1}

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