A particle A with a mass mA is moving with a velocity v and hits a particle B (mass mB) at rest (one dimensional motion). Find the change in the de-Broglie wavelength of the particle A. Treat the collision as elastic.
A particle A with a mass mA is moving with a velocity v and hits a particle B (mass mB) at rest (one dimensional motion). Find the change in the de-Broglie wavelength of the particle A. Treat the collision as elastic.
-
1 Answer
-
Explanation- according to law of conservation of momentum
S0 mAv+mb0=mAv1+mBv2
So mA(v-v1)= mBv2
according to law of conservation of kinetic energy
1/2mAv2=1/2mAv12+1/2mBv22
So mA(v2-v12)= mBv22
From above eqn we can say that v+v1=v2 or v=v2-v1
So v1= v and v2= v
initial=h/mAv
final=h/mAv1=
= final- initial=
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers