<p><strong>A particle executes S.H.M. with amplitude â€&tilde;aâ€™ and time period â€&tilde;Tâ€™. The displacement of the particle when its speed is half of maximum speed is <math><mrow><mfrac><mrow><mroot><mrow><mi>x</mi></mrow><mrow></mrow></mroot><mi>a</mi></mrow><mrow><mn>2</mn></mrow></mfrac><mo>.</mo></mrow></math> The value of x is</strong></p>

v = ω A 2 − s 2 ⇒ A ω 2 = ω A 2 − s 2 ⇒ s = 3 A 2 ⇒ x = 3

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Physics Class 12th Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen Oscillations

A particle executes S.H.M. with amplitude â€˜aâ€™ and time period â€˜Tâ€™. The displacement of the particle when its speed is half of maximum speed is $\frac{\sqrt[]{x} a}{2} .$ The value of x is

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Payal Gupta | Contributor-Level 10

2 months ago

$v = ω \sqrt[]{A^{2} - s^{2}} \Rightarrow \frac{A ω}{2} = ω \sqrt[]{A^{2} - s^{2}} \Rightarrow s = \frac{\sqrt[]{3} A}{2} \Rightarrow x = 3$

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A particle executes S.H.M. with amplitude â€˜aâ€™ and time period â€˜Tâ€™. The displacement of the particle when its speed is half of maximum speed is $\frac{\sqrt[]{x} a}{2} .$ The value of x is

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A particle executes S.H.M. with amplitude â€˜aâ€™ and time period â€˜Tâ€™. The displacement of the particle when its speed is half of maximum speed is xa2. The value of x is

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A particle executes S.H.M. with amplitude â€˜aâ€™ and time period â€˜Tâ€™. The displacement of the particle when its speed is half of maximum speed is $\frac{\sqrt[]{x} a}{2} .$ The value of x is