When a particle executes Simple Hormonic Motion, the nature of graph of velocity as a function of displacement will be:

Option 1 - Circular

Option 2 - Elliptical

Option 3 - Sinusoidal

Option 4 - Straight line

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Answered by

Vishal Baghel | Contributor-Level 10

6 months ago

Correct Option - 2

Detailed Solution:

x = A sin $ω t$

$\Rightarrow v = A ω c o s ω t$

$\Rightarrow v = \pm ω \sqrt[]{A^{2} - x^{2}}$

$\frac{v^{2}}{ω^{2}} + x^{2} = A^{2}$

Elliptical

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