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Physics Class 12th Oscillations Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen

When a particle executes Simple Hormonic Motion, the nature of graph of velocity as a function of displacement will be:

Option 1 -

Circular

Option 2 -

Elliptical

Option 3 -

Sinusoidal

Option 4 -

Straight line

2 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

2 months ago

Correct Option - 2

Detailed Solution:

x = A sin $ω t$

$\Rightarrow v = A ω c o s ω t$

$\Rightarrow v = \pm ω \sqrt[]{A^{2} - x^{2}}$

$\frac{v^{2}}{ω^{2}} + x^{2} = A^{2}$

Elliptical

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