A particle of mass m is projected with speed v at an angle of 30° with the horizontal, find its angular momentum about point of projection when it reaches its maximum height.

Option 1 -

m v 3 1 6 g

Option 2 -

3 m v 3 1 6 g

Option 3 -

m v 3 3 g

Option 4 -

3 m v 3 8 g

0 1 View | Posted 5 days ago
Asked by Shiksha User

  • 1 Answer

  • Correct Option - 2


    Detailed Solution:

    Velocity at maximum height = vcoss30°

    L = m (vcos30) H

    = m v ( 3 2 ) * v 2 s i n 2 3 0 2 g

    = 3 m v 3 1 6 g

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