A particle performs simple harmonic motion with a period of 2 second. The time taken by the particle to cover a displacement equal to half of its amplitude from the mean position is 1/a s. The value of 'a' to the nearest integer is-----------.

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    Answered by

    Raj Pandey | Contributor-Level 9

    2 months ago

    While the particle moves from mean position to displacement, half of its amplitude, its phase changes by π/6 rad. So,
    Time taken, t = (π/6)/ω = T/12 = (2/12)s = (1/6)s
    a = 6

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