A person standing on a balance inside a stationary lift measures 60 kg. The weight of that person if the lift descends with uniform downward acceleration of 1.8m/s2 will be----------N. [g = 10 m/s2]
A person standing on a balance inside a stationary lift measures 60 kg. The weight of that person if the lift descends with uniform downward acceleration of 1.8m/s2 will be----------N. [g = 10 m/s2]
3 Views|Posted 7 months ago
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7 months ago
mg – N = ma
N = m (g – a) = 60 * (10 – 1.8) = 60 * 8.2 = 492 N
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T1 = m (g + a)
T2 = m (g - a)
Apparent weight = mg – ma
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