A photocell works on the principle of

Option 1 - Bernoulli’s principle

Option 2 - Photoelectric effect

Option 3 - Kirchhoff’s rule

Option 4 - Radioactivity law

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Answered by

Alok Kumar Singh | Contributor-Level 10

4 months ago

Correct Option - 2

Detailed Solution:

Photocell works on photoelectric effect.

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Maximum wavelength of light source such that photoelectron can be ejected from material of work function 3 eV is

Alok Kumar Singh

Kindly go through the solution

$λ = \frac{12400}{3} = 4133.3$ Å

In a photoelectric experiment, frequency f = 1.5f₀ (f₀ : threshold frequency). If the frequency of light is changed to f/2, then photocurrent becomes (intensity of light has doubled)

Alok Kumar Singh

Kindly go through the solution

Since $\frac{f}{2} < f_{0}$

->current = 0

Alok Kumar Singh

For no emission of electron

λ > λ₀

Q λ_{0 =}hc/w_0,so λ > hc/w₀

Vishal Baghel

For no emission of electron

$λ > λ_{0}$

$? λ_{0} = \frac{h c}{w_{0}}, s o λ > \frac{h c}{w_{0}}$

Alok Kumar Singh

Case I :- $2 ? - ? = \frac{1}{2} m v_{1}^{2} . . . . . . . . (i)$

Case II :- $10 ? - ? = \frac{1}{2} m v_{2}^{2} . . . . . . . . (i i)$

$\Rightarrow \frac{1}{9} = \frac{v_{1}^{2}}{v_{2}^{2}}$

$\Rightarrow v_{1} : v_{2} = 1 : 3$

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