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Photoelectric Effect Dual Nature of Radiation and Matter Physics Class 12th

A photocell works on the principle of

Option 1 -

Bernoulli's principle

Option 2 -

Photoelectric effect

Option 3 -

Kirchhoff's rule

Option 4 -

Radioactivity law

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1 Answer

Answered by

alok kumar singh | Contributor-Level 10

a month ago

Correct Option - 2

Detailed Solution:

Photocell works on photoelectric effect.

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Similar Questions for you

Maximum wavelength of light source such that photoelectron can be ejected from material of work function 3 eV is

alok kumar singh

Kindly go through the solution

$λ = \frac{12400}{3} = 4133.3$ Å

In a photoelectric experiment, frequency f = 1.5f₀ (f₀ : threshold frequency). If the frequency of light is changed to f/2, then photocurrent becomes (intensity of light has doubled)

alok kumar singh

Kindly go through the solution

Since $\frac{f}{2} < f_{0}$

->current = 0

The work function of a metal is w₀and l is wavelength of incident radiation. There is no emission of photoelectron when

alok kumar singh

For no emission of electron

λ > λ₀

Q λ_{0 =}hc/w_0,so λ > hc/w₀

The work function of a metal is w0 and $λ$ is wavelength of incident radiation. There is no emission of photoelectron when

Vishal Baghel

For no emission of electron

$λ > λ_{0}$

$? λ_{0} = \frac{h c}{w_{0}}, s o λ > \frac{h c}{w_{0}}$

Two stream of photons, possessing energies equal to twice and ten times the work function of metal are incident on the metal surface successively. The value of ratio of maximum velocities of the photoelectrons emitted in the two respective cases is x : y. The value of x is………

alok kumar singh

Case I :- $2 ? - ? = \frac{1}{2} m v_{1}^{2} . . . . . . . . (i)$

Case II :- $10 ? - ? = \frac{1}{2} m v_{2}^{2} . . . . . . . . (i i)$

$\Rightarrow \frac{1}{9} = \frac{v_{1}^{2}}{v_{2}^{2}}$

$\Rightarrow v_{1} : v_{2} = 1 : 3$

->x = 1

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