Maximum wavelength of light source such that photoelectron can be ejected from material of work function 3 eV is

Option 1 - 2133.3 Å

Option 2 - 3133.3 Å

Option 3 - 4133.3 Å

Option 4 - 313.3 Å

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Alok Kumar Singh | Contributor-Level 10

3 months ago

Correct Option - 3

Detailed Solution:

Kindly go through the solution

$λ = \frac{12400}{3} = 4133.3$ Å

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Kindly go through the solution

Since $\frac{f}{2} < f_{0}$

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Case I :- $2 ? - ? = \frac{1}{2} m v_{1}^{2} . . . . . . . . (i)$

Case II :- $10 ? - ? = \frac{1}{2} m v_{2}^{2} . . . . . . . . (i i)$

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