A quantity X is given by (IFv2MLL4) in terms of moment of inertia I, force F, velocity v, work W and Length L. The dimensional formula for x is same as that of:
A quantity X is given by (IFv2MLL4) in terms of moment of inertia I, force F, velocity v, work W and Length L. The dimensional formula for x is same as that of:
Option 1 -
Coefficient of viscosity
Option 2 -
Planck's constant
Option 3 -
Energy density
Option 4 -
Force constant
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1 Answer
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Correct Option - 3
 
 
 Detailed Solution:x = (IFV²)/ (WL? ) 
 I = [ML²]
 F = [MLT? ²]
 V² = [L² T? ²]
 W = [ML² T? ²]
 Q? = [L? ]
 X = [ML? ¹ T? ²]
Similar Questions for you
= Dimensionless
dimensionless
a = dimensionless of b
a = MLT-2
Using F = MA =
m = FTV1
F = ηAdv / dx
η = F (dx/dv) (1/A) = m × a × time × (1/area) = MV/A
Since, should be dimensionless.
So, dimension of
Dimension of 
So,
The dimensional formula for energy E is [ML²T? ²].
The dimensional formula for the gravitational constant G is [M? ¹L³T? ²].
The ratio E/G has dimensions: [ML²T? ²] / [M? ¹L³T? ²] = [M²L? ¹T? ].
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