The work done by a gas molecule in an isolated system is given by , where x is the displacement, k is the Boltzmann constant and T is the temperature. a and b are constants. Then the dimensions of b will be:
The work done by a gas molecule in an isolated system is given by , where x is the displacement, k is the Boltzmann constant and T is the temperature. a and b are constants. Then the dimensions of b will be:
Since, should be dimensionless.
So, dimension of
Dimension of
So,
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= Dimensionless
dimensionless
a = dimensionless of b
a = MLT-2
Using F = MA =
m = FTV1
F = ηAdv / dx
η = F (dx/dv) (1/A) = m × a × time × (1/area) = MV/A
The dimensional formula for energy E is [ML²T? ²].
The dimensional formula for the gravitational constant G is [M? ¹L³T? ²].
The ratio E/G has dimensions: [ML²T? ²] / [M? ¹L³T? ²] = [M²L? ¹T? ].
x = (IFV²)/ (WL? )
I = [ML²]
F = [MLT? ²]
V² = [L² T? ²]
W = [ML² T? ²]
Q? = [L? ]
X = [ML? ¹ T? ²]
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Maths NCERT Exemplar Solutions Class 11th Chapter Eleven 2025
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