A radioactive sample decays with a constant of (1/3)logₑ2 s⁻¹. If initially there are 200 nuclei present, find the number of nuclei decayed during the first 9 seconds.
A radioactive sample decays with a constant of (1/3)logₑ2 s⁻¹. If initially there are 200 nuclei present, find the number of nuclei decayed during the first 9 seconds.
t? , half life = (log?2)/λ = 3 s
Initially 200 nuclei were there
After 3 half-lives, 9 seconds,
No. of nuclei = (1/2³) (200) = 25
Therefore, the number of nuclei that decayed = 200 – 25 = 175
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N = N0e–λt
->t = λN = N0/e
So number of nuclei decayed = N0 – N
= N0 (1- 1/e)
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