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A resistor develops 300 J of thermal energy in 15s, when a current of 2 A is passed through it. If the current increases to 3 A, the energy developed in 10s is……………..J.

0 2 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    3 weeks ago

    H = I 2 R t = 2 2 × R × 1 5

    ⇒ 3 0 0 = 6 0 R

    R = 5 Ω

    Now for 3A, time = 10 sec

    H ' = l 2 R t = 3 2 × 5 × 1 0 = 4 5 0 J

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