A resistor develops 500J of thermal energy in 20 s when a current of 1.5A is passed through it. If the current is increased from 1.5 A to 3 A, what will be the energy developed in 20 s.
A resistor develops 500J of thermal energy in 20 s when a current of 1.5A is passed through it. If the current is increased from 1.5 A to 3 A, what will be the energy developed in 20 s.
Option 1 - <p>2000 J<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>500 J<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>1000 J<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>1500 J</p>
3 Views|Posted 6 months ago
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1 Answer
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6 months ago
Correct Option - 1
Detailed Solution:
Heat generated in the resistance
H = i²RT
H? = 500 = (1.5)²R (20) ⇒ R = 500/45 = 11.11 Ω
H? = (3)²R (20) = 9 * (500/45) * 20 = 2000 J.
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