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A resistor develops 500J of thermal energy in 20 s when a current of 1.5A is passed through it. If the current is increased from 1.5 A to 3 A, what will be the energy developed in 20 s.

Option 1 -

2000 J

Option 2 -

500 J

Option 3 -

1000 J

Option 4 -

1500 J

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 1


    Detailed Solution:

     Heat generated in the resistance
    H = i²RT
    H? = 500 = (1.5)²R (20) ⇒ R = 500/45 = 11.11 Ω
    H? = (3)²R (20) = 9 × (500/45) × 20 = 2000 J.

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