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A resistor dissipates 192 J of energy in 1s when a current of 4A is passed4 through it. Now, when the current is doubled, the amount of thermal energy dissipated in 5s in________J.

0 1 View | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago

    Using Heat equation : H = i2Rt

    =>192 = (4)2 R (1)

    H = (8)2 R (5)

    =>H = 3840 J

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