A rod CD of thermal resistance 10.0 KW-1 is joined at the middle of an identical rod AB as shown in figure. The end A, B and D are maintained at 200°C, 100°C and 125°C respectively. The heat current in CD in P watt. The value of P is……. .

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  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago

    H 1 = H 2 + H 3

    2 0 0 T 5 = T 1 2 5 1 0 + T 1 0 0 5

    T = 1 4 5 ° C H 2 = 1 4 5 1 2 5 1 0 = 2 W

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Δ V L = V 0 γ Δ T

Δ V s = V 0 × 3 × γ 3 × Δ T

Δ V L Δ V S = 0

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Thermal stress is developed on heating when expansion of rod is hindered.

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According to question, we can write

d = d 0 ( 1 + α Δ T ) 6 . 2 4 1 = 6 . 2 3 0 ( 1 + 1 . 4 × 1 0 5 × Δ T )

T = 1 2 6 . 1 8 + 2 7 = 1 5 3 . 1 8 ° C  

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400 × 1 × 12.5 = 500 × 5 × (100 – 36.5)

S = 1 0 6 3 . 5 c a l / g m ° C        

1 g m = 1 6 3 . 5 m o l  

S = 10 cal/mol °C

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d H d t = 2 π x 2 k d T d x

d H d t = 2 π × k × 4 5 1 2 . 5 1 3 = 2 . 2 5 π k W

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