A sample of an ideal gas is taken through the cyclic process ABCA as shown in figure. It absorbs, 40 J of heat during the part AB, no heat during BC and rejects 60 J of heat during CA. A work of 50 J is done on the during the part BC. The internal energy of the gas at A is 1560 J. The work done by the gas during the part CA is:
A sample of an ideal gas is taken through the cyclic process ABCA as shown in figure. It absorbs, 40 J of heat during the part AB, no heat during BC and rejects 60 J of heat during CA. A work of 50 J is done on the during the part BC. The internal energy of the gas at A is 1560 J. The work done by the gas during the part CA is:
Given
QAB = +40J
QBC = 0J
QCA = -60J
WCA =?
WBC = -50J (on the gas)
UA = 1560J
1st Law on path A to B
WAB +
Þ 0 +
Þ UB = UA + 40
= 1560 + 40
UB = 1600 J
1st Low on path B to C
QBC =
Þ 0 = Uc – UD – 50
UC = UB + 50
= 1600 +
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From first law of thermodynamics
From first law of thermodynamics
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