A small ball of mass m is thrown upward with velocity u from the ground. The ball experiences a resistive force m k v 2 where v  is it speed. The maximum height attained by the ball is:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="normal">k</mi> </mrow> </mrow> </mfrac> <mi mathvariant="normal">l</mi> <mi mathvariant="normal">n</mi> <mo>⁡</mo> <mfenced separators="|"> <mrow> <mrow> <mn>1</mn> <mo>+</mo> <mfrac> <mrow> <mrow> <msup> <mrow> <mrow> <mi mathvariant="normal">k</mi> <mi mathvariant="normal">u</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> <mtext> </mtext> <mi mathvariant="normal">g</mi> </mrow> </mrow> </mfrac> </mrow> </mrow> </mfenced> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> <mi mathvariant="normal">k</mi> </mrow> </mrow> </mfrac> <msup> <mrow> <mrow> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">n</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </mrow> </msup> <mo>⁡</mo> <mfrac> <mrow> <mrow> <msup> <mrow> <mrow> <mi mathvariant="normal">k</mi> <mi mathvariant="normal">u</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> </mrow> </mrow> <mrow> <mrow> <mtext> </mtext> <mi mathvariant="normal">g</mi> </mrow> </mrow> </mfrac> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="normal">k</mi> </mrow> </mrow> </mfrac> <msup> <mrow> <mrow> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">n</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </mrow> </msup> <mo>⁡</mo> <mfrac> <mrow> <mrow> <msup> <mrow> <mrow> <mi mathvariant="normal">k</mi> <mi mathvariant="normal">u</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> <mtext> </mtext> <mi mathvariant="normal">g</mi> </mrow> </mrow> </mfrac> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> <mi>k</mi> </mrow> </mrow> </mfrac> <mi mathvariant="normal">l</mi> <mi mathvariant="normal">n</mi> <mo>⁡</mo> <mfenced separators="|"> <mrow> <mrow> <mn>1</mn> <mo>+</mo> <mfrac> <mrow> <mrow> <mi>k</mi> <msup> <mrow> <mrow> <mi>u</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> </mrow> </mrow> <mrow> <mrow> <mi>g</mi> </mrow> </mrow> </mfrac> </mrow> </mrow> </mfenced> </math> </span><strong>&nbsp;</strong>(Newton’s Laws)</p>
3 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
A
7 months ago
Correct Option - 4
Detailed Solution:

Sol. Sol.  Electric field due to infinite sheet is uniform

 

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Similar Questions for you

Let ‘h’ be the height at which velocity becomes equal to magnitude of Acceleration

v = g = 10

v = u + at

10 = 0 + 10t

t = 1 sec

h=ut+12at2

=0×1+12×10×1×1

= 5m

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