A small ball of mass m is thrown upward with velocity u from the ground. The ball experiences a resistive force mkv² where v is it speed. The maximum height attained by the ball is:
A small ball of mass m is thrown upward with velocity u from the ground. The ball experiences a resistive force mkv² where v is it speed. The maximum height attained by the ball is:
Option 1 - <p>1/g ln(1 + ku²/2g)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>1/2k tan⁻¹(ku²/g)</p>
Option 3 - <p>1/2k tan⁻¹(ku²/2g)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>1/2k ln(1 + ku²/g)</p>
21 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
Answered by
5 months ago
Correct Option - 4
Detailed Solution:
Mg + MkV² = MA = -mv (dV/dx)
Vdv = (−) (g + kV²)dx
∫? (Vdv)/ (g + kv²) = ∫? - dx
[ln (g + kV²)/2k]? = -x
ln (g/ (g + ku²) = −2kx
x = (1/2k)ln (1 + ku²/g)
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