A solid sphere of radius R carries a charge Q + q distributed uniformly over its volume. A very small point like piece of it of mass m gets detached from the bottom of the sphere and falls down vertically under gravity. This piece carries charge q. If it acquires a speed v when it has fallen through a vertical height h (see figure), then: (assume the remaining portion to be spherical)

Option 1 - <p>v² = y [qQ / (4πε₀R²ym) + g]</p>
Option 2 - <p>v² = 2y [qQ / (4πε₀R(R+y)m) + g]</p>
Option 3 - <p>v² = y [qQ / (4πε₀(R+y)m) + g]<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 4 - <p>v² = 2y [QqR / (4πε₀(R+y)³m) + g]<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
9 Views|Posted 5 months ago
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5 months ago
Correct Option - 2
Detailed Solution:
Kindly go through the solution

 

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Physics Electrostatic Potential and Capacitance 2025

Physics Electrostatic Potential and Capacitance 2025

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