A solid sphere of radius R carries a charge Q + q distributed uniformly over its volume. A very small point like piece of it of mass m gets detached from the bottom of the sphere and falls down vertically under gravity. This piece carries charge q. If it acquires a speed v when it has fallen through a vertical height h (see figure), then: (assume the remaining portion to be spherical)

Option 1 -

v² = y [qQ / (4πε₀R²ym) + g]

Option 2 -

v² = 2y [qQ / (4πε₀R(R+y)m) + g]

Option 3 -

v² = y [qQ / (4πε₀(R+y)m) + g]

Option 4 -

v² = 2y [QqR / (4πε₀(R+y)³m) + g]

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1 Answer

Answered by

alok kumar singh | Contributor-Level 10

a month ago

Correct Option - 2

Detailed Solution:

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