A square loop of resistance 16 Wis connected with battery of 9 V and internal resistance of 1W. In steady state, find energy stored in capacitor of capacity c = 4 mF as shown (at steady state current divides. symmetrically)
A square loop of resistance 16 Wis connected with battery of 9 V and internal resistance of 1W. In steady state, find energy stored in capacitor of capacity c = 4 mF as shown (at steady state current divides. symmetrically)
Option 1 - <p><span lang="EN-IN">51.84</span><span lang="EN-IN">μ</span><span lang="EN-IN">J</span></p>
Option 2 - <p><span lang="EN-IN">12.96</span><span lang="EN-IN">μ</span><span lang="EN-IN">J</span></p>
Option 3 - <p><span lang="EN-IN">25.92</span><span lang="EN-IN">μ</span><span lang="EN-IN">J</span></p>
Option 4 - <p><span lang="EN-IN">103.68</span><span lang="EN-IN">μ</span><span lang="EN-IN">J</span></p>
8 Views|Posted 4 months ago
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1 Answer
A
Answered by
4 months ago
Correct Option - 3
Detailed Solution:
Equivalent circuit
(VP– VQ) = 0.9 * 6 – 0.9 * 2
VC = 3.6V
U =
= 25.92mJ
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