A system goes from P to Q by two different paths in the P-V diagram as shown in Fig. 12.8. Heat given to the system in path 1 is 1000 J. The work done by the system along path 1 is more than path 2 by 100 J. What is the heat exchanged by the system in path 2?
A system goes from P to Q by two different paths in the P-V diagram as shown in Fig. 12.8. Heat given to the system in path 1 is 1000 J. The work done by the system along path 1 is more than path 2 by 100 J. What is the heat exchanged by the system in path 2?
This is a short answer type question as classified in NCERT Exemplar
For path1
Heat Q1= 1000J
Work done =W1
For path 2
Work done W2= W1-100
As change in internal energy is same
dU=Q1-W1=Q2-W2
1000-W1=Q2-W1+100
Q2= 1000-100= 900J
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Similar Questions for you
From A to B the process is isobaric
= W = 2 × R (600 - 350)
= 500 R
Heat is path dependent so path function but internal energy does not depend on path chosen.
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physics ncert solutions class 11th 2023
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