A thin rod of mass 0.9 kg and length 1 m is suspended, at rest, from one end so that in can freely oscillate in the vertical plane. A particle of move 0.1 kg moving in a straight line with velocity 80 m/s hits the rod at its bottom most point and sticks to it (see figure). The angular speed (in rad/s) of the rod immediately after the collision will be
A thin rod of mass 0.9 kg and length 1 m is suspended, at rest, from one end so that in can freely oscillate in the vertical plane. A particle of move 0.1 kg moving in a straight line with velocity 80 m/s hits the rod at its bottom most point and sticks to it (see figure). The angular speed (in rad/s) of the rod immediately after the collision will be
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1 Answer
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L_i = L_f
mvL = Iω
mvL = (ML³/3 + mL²)ω
Before collision
After collision
0.1 × 80 × 1 = (0.9 × 1²)/3 + 0.1 × 1²)ω
8 = (3/10 + 1/10)ω 8 = (4/10)ω ω = 20 rad/sec
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