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A transistor is connected in common emitter circuit configuration, then collector supply voltage is 10 V and the voltage drop across a resistor of 1000Ω in the collector is 0.6 V. If the current gain factor (β) is 24, then the base current is _______ µA. (Round off to the Nearest Integer)

0 2 Views | Posted a month ago
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    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago

    As we know, β = Ic/Ib = 24 (Given)
    R = 1000Ω, ΔV = 0.6V, Ic = ΔV/R = 0.6/1000 = 6×10? A
    So, Ib = Ic/β = (6×10? )/24 = 25×10? A
    or Ib = 25µA

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