A tuning fork A, marked 512 Hz, produces 5 beats per second, where sounded with another unmarked tuning fork B. If B is loaded with wax the number of beats is again 5 per second. What is the frequency of the tuning fork B when not loaded?

4 Views|Posted 7 months ago
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7 months ago

This is a short answer type question as classified in NCERT Exemplar

Frequency of tuning fork A

v A = 512 Hz

Probable frequency of tuning fork B

v B = v A + 5 = 512 ± 5 = 517 Hz or 507Hz

When B is loaded its frequency reduces .

If it is 517Hz it might reduced to 507Hz given again a beat of 5Hz

If it 507Hz reduction will always increase the

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Physics NCERT Exemplar Solutions Class 11th Chapter Fifteen 2025

Physics NCERT Exemplar Solutions Class 11th Chapter Fifteen 2025

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