A two point charges and are fixed on the -axis at and , respectively. If a third point charge ' ' is taken from the origin to along the semicircle as shown in the figure, the energy of the charge will:
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A two point charges and are fixed on the -axis at and , respectively. If a third point charge ' ' is taken from the origin to along the semicircle as shown in the figure, the energy of the charge will:
Similar Questions for you
E = E? (1 − ax²)
F = qE?
acceleration = F/m = (qE? /m) (1 - ax²) = v (dv/dx)
(qE? /m) ∫? (1 - ax²)dx = ∫? vdv; (qE? /M) (x - ax³/3) = 0
x (1 - ax²/3) = 0; x = 0 & x = √ (3/a)
V = E (1 - e? /τ)
Where τ = RC = 100 × 10? = 10? sec
50V = 100V (1 - e? /10? )
1/2 = 1 - e? ¹?
1/2 = e? ¹?
-ln2 = -10? t
t = ln2/10?
t = 0.693 × 10? sec
According to question, we can write
For maxima of force
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